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Pressure drops in air supply lines.
D P = L x 1,6 x 1012 x qv1.85 / d5 x Pa
Where: D P = pressure drop in kPa
L = length of line or hose in m
qv = air flow in m3/sec (i.e. the air consumption of the ejector)
d = inside diameter of line or hose in mm
Pa = Absolute air pressure at the beginning of the line in kPa.
SYMBOLS, UNITS AND CONVERSION FACTORS
Symbols
A = Area
D or f = Diameter
F = Force [Newton, N]
g = gravitational acceleration [kg/s2]
P = Pressure (SI-unit is Pascal, Pa)(1 Pa = 1 N/m2)
D P = Pressure difference [kPa]
P- = sub atmospheric pressure (-kPa)
P+ = pressure above atmospheric pressure
Unit Conversion Factors
To convert from -------- To --------- Multiply by -------- or To -------- Multiply by
Pressure, stress (force per unit area)
Atmosphere
(normal,760 torr) --------Pa -------- 1,013 x 105 ---------------kPa ------------101,3
Inch of mercury ---------Pa ---------3,377 x 103 ----------kPa -------------3,377
Kilogram-force/cm2 -----Pa ---------9,807 x 104 ----------kPa -------------98,07
mm of mercury ----------Pa ---------1,333 x 102 ----------------Pa ---------------------133,3
pound-force/sqFoot -----Pa ---------4,788 x 10 -----------Pa --------------47,88
pound-force/sqInch -----Pa ---------6,895 x 103 ----------kPa -------------6,895
bar ---------------------Pa ----------1,0 x 105 ------------kPa ---------------------100
torr ---------------------Pa ---------133,322 --------------kPa --------------------0,133
Volume per unit time
foot3/ min (cfm) --------m3/s --------4,719 x 104 ----------dm3/s------------- 0,4719
foot3/ sec --------------m3/s ---------2,832 x 102 ---------dm3/s --------------28,32
gallon/min -------------m3/s ---------6,309 x 105 ----------cm3/s --------------63,09
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